For tomorrow, complete all the calculations posted for you starting last Thursday. Also review the derivation of the elastic collision posted on Decemeber 4.
Here is a sample fuel use calculation
A power plant produces 500,000,000 watts of power. It produces power with an efficiency of 40%? How much deuterium and tritium (DT) fuel does it use in 1 hour?
It produces 500,000,000 J/s x 3600 s/hr = 1.8E12 J/hr. [ E12 means x10 to the 12th] To do this at 40 % efficiency means it uses about 1.8E12J/.4 = 4.5E12 of fuel energy per hour.
Each reaction produces 17.5 Mev which equals 17.5 x1.6 E-13(J/Mev)= 2.8E-12J
Therefore plant needs 4.5E12(J/hr) divided by 2.8E-12 J/reaction = 1.6E24 reactions per hour.
Each reaction uses 2 nuclei, one containing two nucleons and one containing three nucleons, for a total of 5 nucleons per reaction. This comes out to 5 x 1.67 kg per reaction. You are now on your own to calculate kg of fuel used per hour.
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment