The general solution we developed was Dx = vx Dt and Dt = (vyf - vyi)/ay
and vyf = sqrt ( 2ayDy+ vyi squared)
so we have the ugly but useful:
Dx = vx [sqrt ( 2ayDy+ vyi squared)-vyi]/ay
Now rememeber that
ay =-g;
vx vicosthetaH; and
vyi = vi cos thetaV
and you are all set to solve some tough problems like those on worksheet 2.
Friday, February 1, 2008
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