For the faint of heart, here are the solutions:
1)rboy =25 xg x1.5/( 33 xg) =1.13 m
2) M2 =24 x 1.5/1.25 = 28.8 kg
3)M2 g= (-20 g x 0.5+25 g x 1.0)/ 1.75 or M2 = 8 kg
4) take torque around east pier Fwest = (7.5x10^6 x100m + 5x10^6 x150m)/200m = 8.25x10^6N
Feast total weight - Fwest = 13.5x10^6 - 8.25x10^6N = 5.25x10^6
5) FT cos 30 = 500Nx.8m/1.6m =250 N FT = 250/cos30 = 288N
Monday, November 2, 2009
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